4y/y^2-1+y-1/y+1

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Solution for 4y/y^2-1+y-1/y+1 equation: 


D( y )

y = 0

y^2 = 0

y = 0

y = 0

y^2 = 0

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in (-oo:0) U (0:+oo)

y+(4*y)/(y^2)-(1/y)-1+1 = 0

y+(4*y)/(y^2)-y^-1-1+1 = 0

1*y^1+3*y^-1 = 0

(1*y^2+3*y^0)/(y^1) = 0 // * y^2

y^1*(1*y^2+3*y^0) = 0

y^1

y^2+3 = 0

y^2+3 = 0

DELTA = 0^2-(1*3*4)

DELTA = -12

DELTA < 0

y in { } 

y belongs to the empty set

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